x^2-2xy+y^2-2x+2y-3
来源:百度知道 编辑:UC知道 时间:2024/05/26 23:09:19
yin shi fen jie xie xie
x^2-2xy+y^2-2x+2y-3
=(x-y)^2-2(x-y)-3
=(x-y-3)(x-y+1)
可以把x-y设为z这样更好解
x^2-2xy+y^2-2x+2y-3
=(x-y)^2-2(x-y+1)-1
=(x-y-1)(x-y+1)-2(x-y+1)
=(x-y-3)(x-y+1)
这个很简单啊,前三项划成差的平方,四五项提出-2 ,然后把X-Y看成一个因式,在用十字相乘法就搞定了
(x-y-3)(x-y+1)
什么意思
x(x-y)(X^2-xy-y^2)-x^2y(y-x)=多少
因式分解 x^2(x+y)(x-y)-xy(x+y)(y-x)
x^2y-x+xy=x(xy-1+y)能不能分解因式成x(xy-1+y)?
计算(x-y)(x^2+xy+y^2)得
计算:(X+Y)(X^2-XY+Y^2)
xy=2,x+y=2,求x,y.
分解因式:x^-xy-2y^-x+5y-2
(xy-1)^2+(x+y-z)(x+y-zxy)因式分解
代数 x^-y^/ x^-(y-z)^ 除以 x^+2xy+y^/(x-y)^-z^ 乘 x^+xy-xz/x^-xy
xy/x+y=3求2x-3xy+2y/3xy-x-y的值